20p^2=14-18p

Solution for 20p^2=14-18p equation:

20p^2=14-18p

We move all terms to the left:

20p^2-(14-18p)=0

We add all the numbers together, and all the variables

20p^2-(-18p+14)=0

We get rid of parentheses

20p^2+18p-14=0

a = 20; b = 18; c = -14;
Δ = b2-4ac
Δ = 182-4·20·(-14)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-38}{2*20}=\frac{-56}{40}
=-1+2/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+38}{2*20}=\frac{20}{40}
=1/2
$